2(y+4)+4(y+5)=58

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Solution for 2(y+4)+4(y+5)=58 equation: 



2(y+4)+4(y+5)=58

We move all terms to the left:

2(y+4)+4(y+5)-(58)=0

We multiply parentheses

2y+4y+8+20-58=0

We add all the numbers together, and all the variables

6y-30=0

We move all terms containing y to the left, all other terms to the right

6y=30

y=30/6

y=5

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