2(y+4)-3;y=2

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Solution for 2(y+4)-3;y=2 equation: 



2(y+4)-3y=2

We move all terms to the left:

2(y+4)-3y-(2)=0

We add all the numbers together, and all the variables

-3y+2(y+4)-2=0

We multiply parentheses

-3y+2y+8-2=0

We add all the numbers together, and all the variables

-1y+6=0

We move all terms containing y to the left, all other terms to the right

-y=-6

y=-6/-1

y=+6

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