2(y+4)=-4(3y-5)+4y

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Solution for 2(y+4)=-4(3y-5)+4y equation:



2(y+4)=-4(3y-5)+4y
We move all terms to the left:
2(y+4)-(-4(3y-5)+4y)=0
We multiply parentheses
2y-(-4(3y-5)+4y)+8=0
We calculate terms in parentheses: -(-4(3y-5)+4y), so:
-4(3y-5)+4y
We add all the numbers together, and all the variables
4y-4(3y-5)
We multiply parentheses
4y-12y+20
We add all the numbers together, and all the variables
-8y+20
Back to the equation:
-(-8y+20)
We get rid of parentheses
2y+8y-20+8=0
We add all the numbers together, and all the variables
10y-12=0
We move all terms containing y to the left, all other terms to the right
10y=12
y=12/10
y=1+1/5

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