2(y+4)=-4(3y-5)+4y

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Solution for 2(y+4)=-4(3y-5)+4y equation: 



2(y+4)=-4(3y-5)+4y

We move all terms to the left:

2(y+4)-(-4(3y-5)+4y)=0

We multiply parentheses

2y-(-4(3y-5)+4y)+8=0



We calculate terms in parentheses: -(-4(3y-5)+4y), so:

-4(3y-5)+4y

We add all the numbers together, and all the variables

4y-4(3y-5)

We multiply parentheses

4y-12y+20

We add all the numbers together, and all the variables

-8y+20

Back to the equation:

-(-8y+20)



We get rid of parentheses

2y+8y-20+8=0

We add all the numbers together, and all the variables

10y-12=0

We move all terms containing y to the left, all other terms to the right

10y=12

y=12/10

y=1+1/5

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