2(y+4)=-4(6y-3)+8y

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Solution for 2(y+4)=-4(6y-3)+8y equation: 



2(y+4)=-4(6y-3)+8y

We move all terms to the left:

2(y+4)-(-4(6y-3)+8y)=0

We multiply parentheses

2y-(-4(6y-3)+8y)+8=0



We calculate terms in parentheses: -(-4(6y-3)+8y), so:

-4(6y-3)+8y

We add all the numbers together, and all the variables

8y-4(6y-3)

We multiply parentheses

8y-24y+12

We add all the numbers together, and all the variables

-16y+12

Back to the equation:

-(-16y+12)



We get rid of parentheses

2y+16y-12+8=0

We add all the numbers together, and all the variables

18y-4=0

We move all terms containing y to the left, all other terms to the right

18y=4

y=4/18

y=2/9

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