2(y+4)=5(y-3)-1

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Solution for 2(y+4)=5(y-3)-1 equation: 



2(y+4)=5(y-3)-1

We move all terms to the left:

2(y+4)-(5(y-3)-1)=0

We multiply parentheses

2y-(5(y-3)-1)+8=0



We calculate terms in parentheses: -(5(y-3)-1), so:

5(y-3)-1

We multiply parentheses

5y-15-1

We add all the numbers together, and all the variables

5y-16

Back to the equation:

-(5y-16)



We get rid of parentheses

2y-5y+16+8=0

We add all the numbers together, and all the variables

-3y+24=0

We move all terms containing y to the left, all other terms to the right

-3y=-24

y=-24/-3

y=+8

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