2(y+5)(y-5)=48

Solution for 2(y+5)(y-5)=48 equation:

Simplifying
2(y + 5)(y + -5) = 48

Reorder the terms:
2(5 + y)(y + -5) = 48

Reorder the terms:
2(5 + y)(-5 + y) = 48

Multiply (5 + y) * (-5 + y)
2(5(-5 + y) + y(-5 + y)) = 48
2((-5 * 5 + y * 5) + y(-5 + y)) = 48
2((-25 + 5y) + y(-5 + y)) = 48
2(-25 + 5y + (-5 * y + y * y)) = 48
2(-25 + 5y + (-5y + y2)) = 48

Combine like terms: 5y + -5y = 0
2(-25 + 0 + y2) = 48
2(-25 + y2) = 48
(-25 * 2 + y2 * 2) = 48
(-50 + 2y2) = 48

Solving
-50 + 2y2 = 48

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '50' to each side of the equation.
-50 + 50 + 2y2 = 48 + 50

Combine like terms: -50 + 50 = 0
0 + 2y2 = 48 + 50
2y2 = 48 + 50

Combine like terms: 48 + 50 = 98
2y2 = 98

Divide each side by '2'.
y2 = 49

Simplifying
y2 = 49

Take the square root of each side:
y = {-7, 7}