2(y+5)=-3(6y-2)+8y

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Solution for 2(y+5)=-3(6y-2)+8y equation: 



2(y+5)=-3(6y-2)+8y

We move all terms to the left:

2(y+5)-(-3(6y-2)+8y)=0

We multiply parentheses

2y-(-3(6y-2)+8y)+10=0



We calculate terms in parentheses: -(-3(6y-2)+8y), so:

-3(6y-2)+8y

We add all the numbers together, and all the variables

8y-3(6y-2)

We multiply parentheses

8y-18y+6

We add all the numbers together, and all the variables

-10y+6

Back to the equation:

-(-10y+6)



We get rid of parentheses

2y+10y-6+10=0

We add all the numbers together, and all the variables

12y+4=0

We move all terms containing y to the left, all other terms to the right

12y=-4

y=-4/12

y=-1/3

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