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2(y+5)=3(2y-6)
We move all terms to the left:
2(y+5)-(3(2y-6))=0
We multiply parentheses
2y-(3(2y-6))+10=0
We calculate terms in parentheses: -(3(2y-6)), so:We get rid of parentheses
3(2y-6)
We multiply parentheses
6y-18
Back to the equation:
-(6y-18)
2y-6y+18+10=0
We add all the numbers together, and all the variables
-4y+28=0
We move all terms containing y to the left, all other terms to the right
-4y=-28
y=-28/-4
y=+7
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