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2(y+5)=5(2-3y)
We move all terms to the left:
2(y+5)-(5(2-3y))=0
We add all the numbers together, and all the variables
2(y+5)-(5(-3y+2))=0
We multiply parentheses
2y-(5(-3y+2))+10=0
We calculate terms in parentheses: -(5(-3y+2)), so:We get rid of parentheses
5(-3y+2)
We multiply parentheses
-15y+10
Back to the equation:
-(-15y+10)
2y+15y-10+10=0
We add all the numbers together, and all the variables
17y=0
y=0/17
y=0
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