2(y+6)/(3+x)=(2+2y)/(x+1)

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Solution for 2(y+6)/(3+x)=(2+2y)/(x+1) equation: 


D( x )

x+1 = 0

x+3 = 0

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x+3 = 0

x+3 = 0

x+3 = 0 // - 3

x = -3

x in (-oo:-3) U (-3:-1) U (-1:+oo)

(2*(y+6))/(x+3) = (2*y+2)/(x+1) // - (2*y+2)/(x+1)

(2*(y+6))/(x+3)-((2*y+2)/(x+1)) = 0

(2*(y+6))/(x+3)+(-1*(2*y+2))/(x+1) = 0

(2*(y+6)*(x+1))/((x+3)*(x+1))+(-1*(2*y+2)*(x+3))/((x+3)*(x+1)) = 0

2*(y+6)*(x+1)-1*(2*y+2)*(x+3) = 0

10*x-4*y+6 = 0

(10*x-4*y+6)/((x+3)*(x+1)) = 0

(10*x-4*y+6)/((x+3)*(x+1)) = 0 // * (x+3)*(x+1)

10*x-4*y+6 = 0

10*x-4*y+6 = 0 // - 6-4*y

10*x = -(6-4*y) // : 10

x = (-(6-4*y))/10

x = (-(6-4*y))/10

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