2(y+6)=3(y-7+y+3)

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Solution for 2(y+6)=3(y-7+y+3) equation: 



2(y+6)=3(y-7+y+3)

We move all terms to the left:

2(y+6)-(3(y-7+y+3))=0

We add all the numbers together, and all the variables

2(y+6)-(3(2y-4))=0

We multiply parentheses

2y-(3(2y-4))+12=0



We calculate terms in parentheses: -(3(2y-4)), so:

3(2y-4)

We multiply parentheses

6y-12

Back to the equation:

-(6y-12)



We get rid of parentheses

2y-6y+12+12=0

We add all the numbers together, and all the variables

-4y+24=0

We move all terms containing y to the left, all other terms to the right

-4y=-24

y=-24/-4

y=+6

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