2(y+6)=3y+12-y

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Solution for 2(y+6)=3y+12-y equation: 


Simplifying
2(y + 6) = 3y + 12 + -1y

Reorder the terms:
2(6 + y) = 3y + 12 + -1y
(6 * 2 + y * 2) = 3y + 12 + -1y
(12 + 2y) = 3y + 12 + -1y

Reorder the terms:
12 + 2y = 12 + 3y + -1y

Combine like terms: 3y + -1y = 2y
12 + 2y = 12 + 2y

Add '-12' to each side of the equation.
12 + -12 + 2y = 12 + -12 + 2y

Combine like terms: 12 + -12 = 0
0 + 2y = 12 + -12 + 2y
2y = 12 + -12 + 2y

Combine like terms: 12 + -12 = 0
2y = 0 + 2y
2y = 2y

Add '-2y' to each side of the equation.
2y + -2y = 2y + -2y

Combine like terms: 2y + -2y = 0
0 = 2y + -2y

Combine like terms: 2y + -2y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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