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2(y+7)y=4
We move all terms to the left:
2(y+7)y-(4)=0
We multiply parentheses
2y^2+14y-4=0
a = 2; b = 14; c = -4;
Δ = b2-4ac
Δ = 142-4·2·(-4)
Δ = 228
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{228}=\sqrt{4*57}=\sqrt{4}*\sqrt{57}=2\sqrt{57}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{57}}{2*2}=\frac{-14-2\sqrt{57}}{4} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{57}}{2*2}=\frac{-14+2\sqrt{57}}{4} $
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