2(y-)=3(y-4)-y

Solution for 2(y-)=3(y-4)-y equation:

2(y-)=3(y-4)-y

We move all terms to the left:

2(y-)-(3(y-4)-y)=0

We add all the numbers together, and all the variables

2(+y)-(3(y-4)-y)=0

We multiply parentheses

2y-(3(y-4)-y)=0


We calculate terms in parentheses: -(3(y-4)-y), so:

3(y-4)-y

We add all the numbers together, and all the variables

-1y+3(y-4)

We multiply parentheses

-1y+3y-12

We add all the numbers together, and all the variables

2y-12

Back to the equation:

-(2y-12)


We get rid of parentheses

2y-2y+12=0

We add all the numbers together, and all the variables

12!=0

There is no solution for this equation