2(y-1)+(y+3)=13

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Solution for 2(y-1)+(y+3)=13 equation: 



2(y-1)+(y+3)=13

We move all terms to the left:

2(y-1)+(y+3)-(13)=0

We multiply parentheses

2y+(y+3)-2-13=0

We get rid of parentheses

2y+y+3-2-13=0

We add all the numbers together, and all the variables

3y-12=0

We move all terms containing y to the left, all other terms to the right

3y=12

y=12/3

y=4

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