2(y-1)+3y=-(y-1)+y

Solution for 2(y-1)+3y=-(y-1)+y equation:

2(y-1)+3y=-(y-1)+y

We move all terms to the left:

2(y-1)+3y-(-(y-1)+y)=0

We add all the numbers together, and all the variables

3y+2(y-1)-(-(y-1)+y)=0

We multiply parentheses

3y+2y-(-(y-1)+y)-2=0


We calculate terms in parentheses: -(-(y-1)+y), so:

-(y-1)+y

We add all the numbers together, and all the variables

y-(y-1)

We get rid of parentheses

y-y+1

We add all the numbers together, and all the variables

1

Back to the equation:

-(1)


We add all the numbers together, and all the variables

5y-3=0

We move all terms containing y to the left, all other terms to the right

5y=3

y=3/5

y=3/5