2(y-1)+4y=3(2y-1)+8

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Solution for 2(y-1)+4y=3(2y-1)+8 equation: 



2(y-1)+4y=3(2y-1)+8

We move all terms to the left:

2(y-1)+4y-(3(2y-1)+8)=0

We add all the numbers together, and all the variables

4y+2(y-1)-(3(2y-1)+8)=0

We multiply parentheses

4y+2y-(3(2y-1)+8)-2=0



We calculate terms in parentheses: -(3(2y-1)+8), so:

3(2y-1)+8

We multiply parentheses

6y-3+8

We add all the numbers together, and all the variables

6y+5

Back to the equation:

-(6y+5)



We add all the numbers together, and all the variables

6y-(6y+5)-2=0

We get rid of parentheses

6y-6y-5-2=0

We add all the numbers together, and all the variables

-7!=0

There is no solution for this equation

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