2(y-1)+4y=3(y-1+7

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Solution for 2(y-1)+4y=3(y-1+7 equation: 



2(y-1)+4y=3(y-1+7

We move all terms to the left:

2(y-1)+4y-(3(y-1+7)=0

We add all the numbers together, and all the variables

2(y-1)+4y-(3(y+6)=0

We add all the numbers together, and all the variables

4y+2(y-1)-(3(y+6)=0

We multiply parentheses

4y+2y-(3(y+6)-2=0

We add all the numbers together, and all the variables

6y-(3(y+6)-2=0

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