2(y-1)+8=6(2y-y)

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Solution for 2(y-1)+8=6(2y-y) equation: 



2(y-1)+8=6(2y-y)

We move all terms to the left:

2(y-1)+8-(6(2y-y))=0

We add all the numbers together, and all the variables

2(y-1)-(6(+y))+8=0

We multiply parentheses

2y-(6(+y))-2+8=0



We calculate terms in parentheses: -(6(+y)), so:

6(+y)

We multiply parentheses

6y

Back to the equation:

-(6y)



We add all the numbers together, and all the variables

-4y+6=0

We move all terms containing y to the left, all other terms to the right

-4y=-6

y=-6/-4

y=1+1/2

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