2(y-1)-3(y-2)=2(y+5)-4(y-3)

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Solution for 2(y-1)-3(y-2)=2(y+5)-4(y-3) equation: 



2(y-1)-3(y-2)=2(y+5)-4(y-3)

We move all terms to the left:

2(y-1)-3(y-2)-(2(y+5)-4(y-3))=0

We multiply parentheses

2y-3y-(2(y+5)-4(y-3))-2+6=0



We calculate terms in parentheses: -(2(y+5)-4(y-3)), so:

2(y+5)-4(y-3)

We multiply parentheses

2y-4y+10+12

We add all the numbers together, and all the variables

-2y+22

Back to the equation:

-(-2y+22)



We add all the numbers together, and all the variables

-1y-(-2y+22)+4=0

We get rid of parentheses

-1y+2y-22+4=0

We add all the numbers together, and all the variables

y-18=0

We move all terms containing y to the left, all other terms to the right

y=18

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