2(y-1)-5=-3(-8y+3)-4y

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Solution for 2(y-1)-5=-3(-8y+3)-4y equation: 



2(y-1)-5=-3(-8y+3)-4y

We move all terms to the left:

2(y-1)-5-(-3(-8y+3)-4y)=0

We multiply parentheses

2y-(-3(-8y+3)-4y)-2-5=0



We calculate terms in parentheses: -(-3(-8y+3)-4y), so:

-3(-8y+3)-4y

We add all the numbers together, and all the variables

-4y-3(-8y+3)

We multiply parentheses

-4y+24y-9

We add all the numbers together, and all the variables

20y-9

Back to the equation:

-(20y-9)



We add all the numbers together, and all the variables

2y-(20y-9)-7=0

We get rid of parentheses

2y-20y+9-7=0

We add all the numbers together, and all the variables

-18y+2=0

We move all terms containing y to the left, all other terms to the right

-18y=-2

y=-2/-18

y=1/9

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