2(y-1)-6y=10-2(y-4)

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Solution for 2(y-1)-6y=10-2(y-4) equation: 



2(y-1)-6y=10-2(y-4)

We move all terms to the left:

2(y-1)-6y-(10-2(y-4))=0

We add all the numbers together, and all the variables

-6y+2(y-1)-(10-2(y-4))=0

We multiply parentheses

-6y+2y-(10-2(y-4))-2=0



We calculate terms in parentheses: -(10-2(y-4)), so:

10-2(y-4)

determiningTheFunctionDomain
-2(y-4)+10

We multiply parentheses

-2y+8+10

We add all the numbers together, and all the variables

-2y+18

Back to the equation:

-(-2y+18)



We add all the numbers together, and all the variables

-4y-(-2y+18)-2=0

We get rid of parentheses

-4y+2y-18-2=0

We add all the numbers together, and all the variables

-2y-20=0

We move all terms containing y to the left, all other terms to the right

-2y=20

y=20/-2

y=-10

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