2(y-1)=1/3(3y+6

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Solution for 2(y-1)=1/3(3y+6 equation: 



2(y-1)=1/3(3y+6

We move all terms to the left:

2(y-1)-(1/3(3y+6)=0



Domain of the equation: 3(3y+6)!=0

y∈R



We multiply parentheses

2y-(1/3(3y+6)-2=0

We multiply all the terms by the denominator


2y*3(3y+6)-2-(1=0

We add all the numbers together, and all the variables

2y*3(3y+6)=0

Wy multiply elements

6y^2(3=0

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