2(y-1)=2y+2-2(-8y-7)

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Solution for 2(y-1)=2y+2-2(-8y-7) equation: 



2(y-1)=2y+2-2(-8y-7)

We move all terms to the left:

2(y-1)-(2y+2-2(-8y-7))=0

We multiply parentheses

2y-(2y+2-2(-8y-7))-2=0



We calculate terms in parentheses: -(2y+2-2(-8y-7)), so:

2y+2-2(-8y-7)

determiningTheFunctionDomain
2y-2(-8y-7)+2

We multiply parentheses

2y+16y+14+2

We add all the numbers together, and all the variables

18y+16

Back to the equation:

-(18y+16)



We get rid of parentheses

2y-18y-16-2=0

We add all the numbers together, and all the variables

-16y-18=0

We move all terms containing y to the left, all other terms to the right

-16y=18

y=18/-16

y=-1+1/8

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