2(y-1)=3y-(y+2)

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Solution for 2(y-1)=3y-(y+2) equation:


Simplifying
2(y + -1) = 3y + -1(y + 2)

Reorder the terms:
2(-1 + y) = 3y + -1(y + 2)
(-1 * 2 + y * 2) = 3y + -1(y + 2)
(-2 + 2y) = 3y + -1(y + 2)

Reorder the terms:
-2 + 2y = 3y + -1(2 + y)
-2 + 2y = 3y + (2 * -1 + y * -1)
-2 + 2y = 3y + (-2 + -1y)

Reorder the terms:
-2 + 2y = -2 + 3y + -1y

Combine like terms: 3y + -1y = 2y
-2 + 2y = -2 + 2y

Add '2' to each side of the equation.
-2 + 2 + 2y = -2 + 2 + 2y

Combine like terms: -2 + 2 = 0
0 + 2y = -2 + 2 + 2y
2y = -2 + 2 + 2y

Combine like terms: -2 + 2 = 0
2y = 0 + 2y
2y = 2y

Add '-2y' to each side of the equation.
2y + -2y = 2y + -2y

Combine like terms: 2y + -2y = 0
0 = 2y + -2y

Combine like terms: 2y + -2y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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