2(y-1)=4y+6-2(-8y-3)

Solution for 2(y-1)=4y+6-2(-8y-3) equation:

2(y-1)=4y+6-2(-8y-3)

We move all terms to the left:

2(y-1)-(4y+6-2(-8y-3))=0

We multiply parentheses

2y-(4y+6-2(-8y-3))-2=0


We calculate terms in parentheses: -(4y+6-2(-8y-3)), so:

4y+6-2(-8y-3)

determiningTheFunctionDomain
4y-2(-8y-3)+6

We multiply parentheses

4y+16y+6+6

We add all the numbers together, and all the variables

20y+12

Back to the equation:

-(20y+12)


We get rid of parentheses

2y-20y-12-2=0

We add all the numbers together, and all the variables

-18y-14=0

We move all terms containing y to the left, all other terms to the right

-18y=14

y=14/-18

y=-7/9