2(y-1)=6y+4-2(-3y-4)

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Solution for 2(y-1)=6y+4-2(-3y-4) equation: 



2(y-1)=6y+4-2(-3y-4)

We move all terms to the left:

2(y-1)-(6y+4-2(-3y-4))=0

We multiply parentheses

2y-(6y+4-2(-3y-4))-2=0



We calculate terms in parentheses: -(6y+4-2(-3y-4)), so:

6y+4-2(-3y-4)

determiningTheFunctionDomain
6y-2(-3y-4)+4

We multiply parentheses

6y+6y+8+4

We add all the numbers together, and all the variables

12y+12

Back to the equation:

-(12y+12)



We get rid of parentheses

2y-12y-12-2=0

We add all the numbers together, and all the variables

-10y-14=0

We move all terms containing y to the left, all other terms to the right

-10y=14

y=14/-10

y=-1+2/5

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