2(y-1)=8y+6-3(-2y-2)

Solution for 2(y-1)=8y+6-3(-2y-2) equation:

2(y-1)=8y+6-3(-2y-2)

We move all terms to the left:

2(y-1)-(8y+6-3(-2y-2))=0

We multiply parentheses

2y-(8y+6-3(-2y-2))-2=0


We calculate terms in parentheses: -(8y+6-3(-2y-2)), so:

8y+6-3(-2y-2)

determiningTheFunctionDomain
8y-3(-2y-2)+6

We multiply parentheses

8y+6y+6+6

We add all the numbers together, and all the variables

14y+12

Back to the equation:

-(14y+12)


We get rid of parentheses

2y-14y-12-2=0

We add all the numbers together, and all the variables

-12y-14=0

We move all terms containing y to the left, all other terms to the right

-12y=14

y=14/-12

y=-1+1/6