2(y-13)=4(2y+1)

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Solution for 2(y-13)=4(2y+1) equation: 



2(y-13)=4(2y+1)

We move all terms to the left:

2(y-13)-(4(2y+1))=0

We multiply parentheses

2y-(4(2y+1))-26=0



We calculate terms in parentheses: -(4(2y+1)), so:

4(2y+1)

We multiply parentheses

8y+4

Back to the equation:

-(8y+4)



We get rid of parentheses

2y-8y-4-26=0

We add all the numbers together, and all the variables

-6y-30=0

We move all terms containing y to the left, all other terms to the right

-6y=30

y=30/-6

y=-5

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