2(y-2)+3(2y+4)=32

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Solution for 2(y-2)+3(2y+4)=32 equation:



2(y-2)+3(2y+4)=32
We move all terms to the left:
2(y-2)+3(2y+4)-(32)=0
We multiply parentheses
2y+6y-4+12-32=0
We add all the numbers together, and all the variables
8y-24=0
We move all terms containing y to the left, all other terms to the right
8y=24
y=24/8
y=3

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