2(y-2)-3=-5(-3y+5)-3y

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Solution for 2(y-2)-3=-5(-3y+5)-3y equation: 



2(y-2)-3=-5(-3y+5)-3y

We move all terms to the left:

2(y-2)-3-(-5(-3y+5)-3y)=0

We multiply parentheses

2y-(-5(-3y+5)-3y)-4-3=0



We calculate terms in parentheses: -(-5(-3y+5)-3y), so:

-5(-3y+5)-3y

We add all the numbers together, and all the variables

-3y-5(-3y+5)

We multiply parentheses

-3y+15y-25

We add all the numbers together, and all the variables

12y-25

Back to the equation:

-(12y-25)



We add all the numbers together, and all the variables

2y-(12y-25)-7=0

We get rid of parentheses

2y-12y+25-7=0

We add all the numbers together, and all the variables

-10y+18=0

We move all terms containing y to the left, all other terms to the right

-10y=-18

y=-18/-10

y=1+4/5

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