2(y-2)-5=-2(y+3)

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Solution for 2(y-2)-5=-2(y+3) equation: 



2(y-2)-5=-2(y+3)

We move all terms to the left:

2(y-2)-5-(-2(y+3))=0

We multiply parentheses

2y-(-2(y+3))-4-5=0



We calculate terms in parentheses: -(-2(y+3)), so:

-2(y+3)

We multiply parentheses

-2y-6

Back to the equation:

-(-2y-6)



We add all the numbers together, and all the variables

2y-(-2y-6)-9=0

We get rid of parentheses

2y+2y+6-9=0

We add all the numbers together, and all the variables

4y-3=0

We move all terms containing y to the left, all other terms to the right

4y=3

y=3/4

y=3/4

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