2(y-2)-y=3(y-1)+9

Solution for 2(y-2)-y=3(y-1)+9 equation:

2(y-2)-y=3(y-1)+9

We move all terms to the left:

2(y-2)-y-(3(y-1)+9)=0

We add all the numbers together, and all the variables

-1y+2(y-2)-(3(y-1)+9)=0

We multiply parentheses

-1y+2y-(3(y-1)+9)-4=0


We calculate terms in parentheses: -(3(y-1)+9), so:

3(y-1)+9

We multiply parentheses

3y-3+9

We add all the numbers together, and all the variables

3y+6

Back to the equation:

-(3y+6)


We add all the numbers together, and all the variables

y-(3y+6)-4=0

We get rid of parentheses

y-3y-6-4=0

We add all the numbers together, and all the variables

-2y-10=0

We move all terms containing y to the left, all other terms to the right

-2y=10

y=10/-2

y=-5