2(y-2)=2y+2-2(-9y-2)

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Solution for 2(y-2)=2y+2-2(-9y-2) equation: 



2(y-2)=2y+2-2(-9y-2)

We move all terms to the left:

2(y-2)-(2y+2-2(-9y-2))=0

We multiply parentheses

2y-(2y+2-2(-9y-2))-4=0



We calculate terms in parentheses: -(2y+2-2(-9y-2)), so:

2y+2-2(-9y-2)

determiningTheFunctionDomain
2y-2(-9y-2)+2

We multiply parentheses

2y+18y+4+2

We add all the numbers together, and all the variables

20y+6

Back to the equation:

-(20y+6)



We get rid of parentheses

2y-20y-6-4=0

We add all the numbers together, and all the variables

-18y-10=0

We move all terms containing y to the left, all other terms to the right

-18y=10

y=10/-18

y=-5/9

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