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2(y-2)=3y+8-3(-3y-2)
We move all terms to the left:
2(y-2)-(3y+8-3(-3y-2))=0
We multiply parentheses
2y-(3y+8-3(-3y-2))-4=0
We calculate terms in parentheses: -(3y+8-3(-3y-2)), so:We get rid of parentheses
3y+8-3(-3y-2)
determiningTheFunctionDomain 3y-3(-3y-2)+8
We multiply parentheses
3y+9y+6+8
We add all the numbers together, and all the variables
12y+14
Back to the equation:
-(12y+14)
2y-12y-14-4=0
We add all the numbers together, and all the variables
-10y-18=0
We move all terms containing y to the left, all other terms to the right
-10y=18
y=18/-10
y=-1+4/5
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