2(y-22)+4(y-3)=40

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Solution for 2(y-22)+4(y-3)=40 equation: 


Simplifying
2(y + -22) + 4(y + -3) = 40

Reorder the terms:
2(-22 + y) + 4(y + -3) = 40
(-22 * 2 + y * 2) + 4(y + -3) = 40
(-44 + 2y) + 4(y + -3) = 40

Reorder the terms:
-44 + 2y + 4(-3 + y) = 40
-44 + 2y + (-3 * 4 + y * 4) = 40
-44 + 2y + (-12 + 4y) = 40

Reorder the terms:
-44 + -12 + 2y + 4y = 40

Combine like terms: -44 + -12 = -56
-56 + 2y + 4y = 40

Combine like terms: 2y + 4y = 6y
-56 + 6y = 40

Solving
-56 + 6y = 40

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '56' to each side of the equation.
-56 + 56 + 6y = 40 + 56

Combine like terms: -56 + 56 = 0
0 + 6y = 40 + 56
6y = 40 + 56

Combine like terms: 40 + 56 = 96
6y = 96

Divide each side by '6'.
y = 16

Simplifying
y = 16

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