2(y-3)+3y=9+5(y-3)

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Solution for 2(y-3)+3y=9+5(y-3) equation:


Simplifying
2(y + -3) + 3y = 9 + 5(y + -3)

Reorder the terms:
2(-3 + y) + 3y = 9 + 5(y + -3)
(-3 * 2 + y * 2) + 3y = 9 + 5(y + -3)
(-6 + 2y) + 3y = 9 + 5(y + -3)

Combine like terms: 2y + 3y = 5y
-6 + 5y = 9 + 5(y + -3)

Reorder the terms:
-6 + 5y = 9 + 5(-3 + y)
-6 + 5y = 9 + (-3 * 5 + y * 5)
-6 + 5y = 9 + (-15 + 5y)

Combine like terms: 9 + -15 = -6
-6 + 5y = -6 + 5y

Add '6' to each side of the equation.
-6 + 6 + 5y = -6 + 6 + 5y

Combine like terms: -6 + 6 = 0
0 + 5y = -6 + 6 + 5y
5y = -6 + 6 + 5y

Combine like terms: -6 + 6 = 0
5y = 0 + 5y
5y = 5y

Add '-5y' to each side of the equation.
5y + -5y = 5y + -5y

Combine like terms: 5y + -5y = 0
0 = 5y + -5y

Combine like terms: 5y + -5y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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