2(y-3)+y=3(y-1)

Solution for 2(y-3)+y=3(y-1) equation:

2(y-3)+y=3(y-1)

We move all terms to the left:

2(y-3)+y-(3(y-1))=0

We add all the numbers together, and all the variables

y+2(y-3)-(3(y-1))=0

We multiply parentheses

y+2y-(3(y-1))-6=0


We calculate terms in parentheses: -(3(y-1)), so:

3(y-1)

We multiply parentheses

3y-3

Back to the equation:

-(3y-3)


We add all the numbers together, and all the variables

3y-(3y-3)-6=0

We get rid of parentheses

3y-3y+3-6=0

We add all the numbers together, and all the variables

-3!=0

There is no solution for this equation