2(y-3)-4(y+12)=-2(y+27)

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Solution for 2(y-3)-4(y+12)=-2(y+27) equation:


Simplifying
2(y + -3) + -4(y + 12) = -2(y + 27)

Reorder the terms:
2(-3 + y) + -4(y + 12) = -2(y + 27)
(-3 * 2 + y * 2) + -4(y + 12) = -2(y + 27)
(-6 + 2y) + -4(y + 12) = -2(y + 27)

Reorder the terms:
-6 + 2y + -4(12 + y) = -2(y + 27)
-6 + 2y + (12 * -4 + y * -4) = -2(y + 27)
-6 + 2y + (-48 + -4y) = -2(y + 27)

Reorder the terms:
-6 + -48 + 2y + -4y = -2(y + 27)

Combine like terms: -6 + -48 = -54
-54 + 2y + -4y = -2(y + 27)

Combine like terms: 2y + -4y = -2y
-54 + -2y = -2(y + 27)

Reorder the terms:
-54 + -2y = -2(27 + y)
-54 + -2y = (27 * -2 + y * -2)
-54 + -2y = (-54 + -2y)

Add '54' to each side of the equation.
-54 + 54 + -2y = -54 + 54 + -2y

Combine like terms: -54 + 54 = 0
0 + -2y = -54 + 54 + -2y
-2y = -54 + 54 + -2y

Combine like terms: -54 + 54 = 0
-2y = 0 + -2y
-2y = -2y

Add '2y' to each side of the equation.
-2y + 2y = -2y + 2y

Combine like terms: -2y + 2y = 0
0 = -2y + 2y

Combine like terms: -2y + 2y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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