2(y-3)-4(y-1)=6

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Solution for 2(y-3)-4(y-1)=6 equation: 



2(y-3)-4(y-1)=6

We move all terms to the left:

2(y-3)-4(y-1)-(6)=0

We multiply parentheses

2y-4y-6+4-6=0

We add all the numbers together, and all the variables

-2y-8=0

We move all terms containing y to the left, all other terms to the right

-2y=8

y=8/-2

y=-4

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