2(y-3)-4+4y=2

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Solution for 2(y-3)-4+4y=2 equation: 



2(y-3)-4+4y=2

We move all terms to the left:

2(y-3)-4+4y-(2)=0

We add all the numbers together, and all the variables

4y+2(y-3)-6=0

We multiply parentheses

4y+2y-6-6=0

We add all the numbers together, and all the variables

6y-12=0

We move all terms containing y to the left, all other terms to the right

6y=12

y=12/6

y=2

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