2(y-3)-5(3y-1)=8(1+y)

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Solution for 2(y-3)-5(3y-1)=8(1+y) equation: 



2(y-3)-5(3y-1)=8(1+y)

We move all terms to the left:

2(y-3)-5(3y-1)-(8(1+y))=0

We add all the numbers together, and all the variables

2(y-3)-5(3y-1)-(8(y+1))=0

We multiply parentheses

2y-15y-(8(y+1))-6+5=0



We calculate terms in parentheses: -(8(y+1)), so:

8(y+1)

We multiply parentheses

8y+8

Back to the equation:

-(8y+8)



We add all the numbers together, and all the variables

-13y-(8y+8)-1=0

We get rid of parentheses

-13y-8y-8-1=0

We add all the numbers together, and all the variables

-21y-9=0

We move all terms containing y to the left, all other terms to the right

-21y=9

y=9/-21

y=-3/7

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