2(y-3)-7=-6(-3y+1)-2y

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Solution for 2(y-3)-7=-6(-3y+1)-2y equation:



2(y-3)-7=-6(-3y+1)-2y
We move all terms to the left:
2(y-3)-7-(-6(-3y+1)-2y)=0
We multiply parentheses
2y-(-6(-3y+1)-2y)-6-7=0
We calculate terms in parentheses: -(-6(-3y+1)-2y), so:
-6(-3y+1)-2y
We add all the numbers together, and all the variables
-2y-6(-3y+1)
We multiply parentheses
-2y+18y-6
We add all the numbers together, and all the variables
16y-6
Back to the equation:
-(16y-6)
We add all the numbers together, and all the variables
2y-(16y-6)-13=0
We get rid of parentheses
2y-16y+6-13=0
We add all the numbers together, and all the variables
-14y-7=0
We move all terms containing y to the left, all other terms to the right
-14y=7
y=7/-14
y=-1/2

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