2(y-3)=3(7y-6)+19(y+1)+14

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Solution for 2(y-3)=3(7y-6)+19(y+1)+14 equation:


2(y-3)=3 (7y-6)+19(y+1)+14

We simplify the equation to the form, which is simple to understand 
2(y-3)=3(7y-6)+19(y+1)+14

Reorder the terms in parentheses
+(+2y-6)=3*(7y-6)+19*(y+1)+14

Remove unnecessary parentheses
+2y-6=+3+*(+7y-6+)+19+*(+y+1+)+14

Reorder the terms in parentheses
+2y-6=+(+21y-18)+19*(y+1)+14

Remove unnecessary parentheses
+2y-6=+21y-18+19+*(+y+1+)+14

Reorder the terms in parentheses
+2y-6=+21y-18+(+19y+19)+14

Remove unnecessary parentheses
+2y-6=+21y-18+19y+19+14

We move all terms containing y to the left and all other terms to the right. 
+2y-21y-19y=-18+19+14+6

We simplify left and right side of the equation. 
-38y=+21

We divide both sides of the equation by -38 to get y. 
y=-0.552631578947

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