2(y-3)=3(y-2)

Solution for 2(y-3)=3(y-2) equation:

Simplifying
2(y + -3) = 3(y + -2)

Reorder the terms:
2(-3 + y) = 3(y + -2)
(-3 * 2 + y * 2) = 3(y + -2)
(-6 + 2y) = 3(y + -2)

Reorder the terms:
-6 + 2y = 3(-2 + y)
-6 + 2y = (-2 * 3 + y * 3)
-6 + 2y = (-6 + 3y)

Add '6' to each side of the equation.
-6 + 6 + 2y = -6 + 6 + 3y

Combine like terms: -6 + 6 = 0
0 + 2y = -6 + 6 + 3y
2y = -6 + 6 + 3y

Combine like terms: -6 + 6 = 0
2y = 0 + 3y
2y = 3y

Solving
2y = 3y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3y' to each side of the equation.
2y + -3y = 3y + -3y

Combine like terms: 2y + -3y = -1y
-1y = 3y + -3y

Combine like terms: 3y + -3y = 0
-1y = 0

Divide each side by '-1'.
y = 0

Simplifying
y = 0