2(y-3)=y+2

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Solution for 2(y-3)=y+2 equation: 



2(y-3)=y+2

We move all terms to the left:

2(y-3)-(y+2)=0

We multiply parentheses

2y-(y+2)-6=0

We get rid of parentheses

2y-y-2-6=0

We add all the numbers together, and all the variables

y-8=0

We move all terms containing y to the left, all other terms to the right

y=8

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