2(y-3)=y-3(y+2)

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Solution for 2(y-3)=y-3(y+2) equation: 



2(y-3)=y-3(y+2)

We move all terms to the left:

2(y-3)-(y-3(y+2))=0

We multiply parentheses

2y-(y-3(y+2))-6=0



We calculate terms in parentheses: -(y-3(y+2)), so:

y-3(y+2)

We multiply parentheses

y-3y-6

We add all the numbers together, and all the variables

-2y-6

Back to the equation:

-(-2y-6)



We get rid of parentheses

2y+2y+6-6=0

We add all the numbers together, and all the variables

4y=0

y=0/4

y=0

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