2(y-3)=y-6+y

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Solution for 2(y-3)=y-6+y equation: 



2(y-3)=y-6+y

We move all terms to the left:

2(y-3)-(y-6+y)=0

We add all the numbers together, and all the variables

2(y-3)-(2y-6)=0

We multiply parentheses

2y-(2y-6)-6=0

We get rid of parentheses

2y-2y+6-6=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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