2(y-4)+12=16

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Solution for 2(y-4)+12=16 equation: 



2(y-4)+12=16

We move all terms to the left:

2(y-4)+12-(16)=0

We add all the numbers together, and all the variables

2(y-4)-4=0

We multiply parentheses

2y-8-4=0

We add all the numbers together, and all the variables

2y-12=0

We move all terms containing y to the left, all other terms to the right

2y=12

y=12/2

y=6

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