2(y-4)+3(y-10)=10y+16

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Solution for 2(y-4)+3(y-10)=10y+16 equation:


Simplifying
2(y + -4) + 3(y + -10) = 10y + 16

Reorder the terms:
2(-4 + y) + 3(y + -10) = 10y + 16
(-4 * 2 + y * 2) + 3(y + -10) = 10y + 16
(-8 + 2y) + 3(y + -10) = 10y + 16

Reorder the terms:
-8 + 2y + 3(-10 + y) = 10y + 16
-8 + 2y + (-10 * 3 + y * 3) = 10y + 16
-8 + 2y + (-30 + 3y) = 10y + 16

Reorder the terms:
-8 + -30 + 2y + 3y = 10y + 16

Combine like terms: -8 + -30 = -38
-38 + 2y + 3y = 10y + 16

Combine like terms: 2y + 3y = 5y
-38 + 5y = 10y + 16

Reorder the terms:
-38 + 5y = 16 + 10y

Solving
-38 + 5y = 16 + 10y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-10y' to each side of the equation.
-38 + 5y + -10y = 16 + 10y + -10y

Combine like terms: 5y + -10y = -5y
-38 + -5y = 16 + 10y + -10y

Combine like terms: 10y + -10y = 0
-38 + -5y = 16 + 0
-38 + -5y = 16

Add '38' to each side of the equation.
-38 + 38 + -5y = 16 + 38

Combine like terms: -38 + 38 = 0
0 + -5y = 16 + 38
-5y = 16 + 38

Combine like terms: 16 + 38 = 54
-5y = 54

Divide each side by '-5'.
y = -10.8

Simplifying
y = -10.8

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